:-) "Mike Dunlop" <miked@xxxxxxxxx> wrote in message news:D2C59439-01E0-4153-B5AD-28CFC97D8C19@xxxxxxxxxxxx > My bad - that doesn't work - that came off the top off my head. It > sure did look sexy though, no ? > > - MD > > > >> echo ${"array".$prefix}; > >> > > > > really? did you test that? > > doesn't work when I do it (the second expression does > > - but doesn't answer the OPs question actually imho the > > answer is not eval() either, because its slow and a security > > headache): > > > > > > $array = array(); > > $array["col3"]["col2"] = "Test #2"; > > $prefix = "[\"col3\"][\"col2\"]"; > > echo ${"array".$prefix}, ${"array"}["col3"]["col2"]; > > > > > > > > ----------------------------- > > try something like this instead?: > > (code has been tested) > > > > function getVal($arr, $path) > > { > > $retval = null; > > > > if (!is_array($arr) || empty($arr) || > > !is_array($path) || empty($path)) { > > return null; > > } > > > > while (count($path)) { > > $key = array_shift($path); > > if (!isset($arr[ $key ])) { > > return null; > > } > > $retval = $arr[ $key ]; > > $arr =& $arr[ $key ]; > > } > > > > return $retval; > > } > > $ra = array(); > > $ra["col3"]["col2"] = "Test #2"; > > $path = array("col3","col2"); > > echo getVal($ra, $path); > > > > > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
