Dan Trainor wrote: > Mike Johnson wrote: > >>From: Dan Trainor [mailto:info@xxxxxxxxxxxxxxxx] >> >> >> >>>Hello, all - >>> >>>I've been looking around for a function that would tell me if a $value >>>in a $key=>$value array was empty, and I could not find one. So I >>>decided to make my own. Even if I am re-inventing the wheel, >>>I thought that the practice might be good for me. >>> >>>However, my function doesn't *quite* work, and I'm having a difficult >>>time finding out why. The code is as follows: >>> >>>function findMissingVals($workingArray) { >>> $newcount = count($workingArray); >>> for ($i = 0; $i <= $newcount; $i++) { >>> if (empty($workingArray['$i'])) { >>> return 1; >>> } >>> } >>>} >>> >>>So it takes in $workingArray as an array, runs a loop, checks $i, yada >>>yada. The thing is, that sometimes the function does not >>>return 1, even when it should. >>> >>>I was hoping some experienced eyes could take a gander at >>>this and give me some pointers. >> >> >>PHP doesn't eval code in single-quotes, so what you want to do is >>simply: >> >>if (empty($workingArray[$i])) { >> return 1; >>} >> >>With the single-quotes, it's looking for the string $i as a key. >> >>HTH! >> > > > > Hey there, Mike - > > Your tips were very helpful, thank you. I saw my error, but I am still > having problems. Being somewhat novice to PHP, I think my error might > very well just be in my implementation of the function, as follows: > > function findMissingVals($workingArray) { > $newcount = count($workingArray); > for ($i = 0; $i <= $newcount; $i++) { > if (empty($workingArray[$i])) { > return 1; > } > } > } > > if (findMissingVals($vars)) { > if (!$var1) { ?> hi1 <? }; > if (!$var2) { ?> hi2 <? }; > if (!$var3) { ?> hi3 <? }; > if (!$var4) { ?> hi4 <? }; > if (!$var5) { ?> hi5 <? }; > if (!$var6) { ?> hi6 <? }; > } else { > echo "hi"; > } > > > I never see "hi", even if I have an array as $vars as such: > > $vars = array("one","two","","four","five"); > > so I'm a bit confused. > > If you wouldn't mind taking another few minutes here, I would greatly > appreciate it. > > Thanks! > -dant > Er, sorry about that - I never see "hi" even if an array is set as such: $vars = array("one","two","three","four","five"); but I do see "hi3" if I have an array set as such: $vars = array("one","two","","four","five"); Thanks! -dant -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
