As with my previous post the problem is the pieces of the array can vary from 1 to 4 items. So pieces 3 and 4 are often undefined giving the 'undefined index' notice. All I really want to do is display the array pieces if they EXIST. But as they are inside a echo statement so I can't even to a for loop...can I? Any ideas? R. if ($quantity == 0){ } else { $pieces = explode(" ", $quantity); $formatted_price = sprintf('%0.2f', $pricecode); echo "<table width=\"240\" border=\"0\" cellpadding=\"2\" cellspacing=\"5\"><tr><td valign=\"top\" align=\"right\" width=\"40\">$pieces[0]</td><td align=\"left\" width=\"60\"></td><td align=\"left\" width=\"200\">$pieces[1] $pieces[2] $pieces[3] $pieces[4]</td><td valign=\"top\" align=\"left\" width=\"80\">$formatted_price</td></tr></table>"; } } -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php