Re: Passing variable number of parameters by reference

Marek Kilimajer <lists@xxxxxxxxxxxxx> · Fri, 13 May 2005 04:24:21 +0200

I believe it's mentioned somewhere in the manual you can't do that. 
func_get_arg() always return a copy. You can workaround this using an array.

Robert Meyer wrote:
Hello,

Using: PHP Version 5.0.3

I build the following function:

    function Set4HTMLOut() {
      $C = func_num_args();
      for ($I = 0; $I < $C; $I++) {
        $A = func_get_arg($I);
 echo 'I['.$I.']('.strlen($A).'): '.$A.'<br />';
        $A = htmlspecialchars($A);
 echo 'I['.$I.']('.strlen($A).'): '.$A.'<br />';
      }
    }

And called it like this:

     Set4HTMLOut(&$LName, &$LOrg, &$LWebSite, &$LPhones, &$LComments);
 echo '<br />After call:<br />'.
         'LName: '.$LName.'<br />'.
         'LOrg: '.$LOrg.'<br />'.
         'LWebSite: '.$LWebSite.'<br />'.
         'LPhones: '.$LPhones.'<br />'.
         'LComments: '.$LComments.'<br />';

The "echo" statements in the Set4HTMLOut() function echos all the correct 
data and proves the data was received correctly then altered by the 
htmlspecialchars() function appropriately.  Notice that the caller passes 
each variable as a reference.  Yet, the "echo" statement after the call 
displays the data without any changes, like the first "echo" statement in 
the Set$HTMLOut() function does.

Is it not possible to pass variables by reference to a variable-length 
parameter list?  Or am I doing something wrong?  If so, what?

I have already built a work around.  I do not need any work arounds.  I just 
think one should be able to pass variables by reference to a function that 
accepts a variable-length parameter list.

Regards

Robert

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