Hi All,
ok, this revised code produces the error below,
<?php
mysql_select_db("status",$db);
$maker_result = mysql_query("SELECT Makers.maker_id Makers.maker_detail FROM Makers",$db);
$maker_num = mysql_num_rows($maker_result); //Line 40
?>
<select name="slct_maker">
<?php
for ($i=0; $i<$maker_num; $i++){
$maker_myrow=mysql_fetch_array($maker_result);
$maker=mysql_result($maker_result,$i,"maker_detail");
$maker_id=mysql_result($maker_result,$i,"maker_id");
echo "<option value=\"$maker_id\">$maker</option><br>";
}
?>
</select>
*Warning*: mysql_num_rows(): supplied argument is not a valid MySQL result resource in */var/www/html/products.php* on line *40
Cheers.
Mark Sargent. *
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