On 5/9/05, Martín Marqués <martin@xxxxxxxxxxxxxxx> wrote: > I have a text variable that contains "$" symbols, that when I pass it out PHP > thinks that the "$" mean that a variable name comes right after. > > I tried escaping the "$" put with no luck. > > Is there something I can do? $var = 'hi $there'; -- Victor Saldaña D. User #330054 counter.li.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
