On 5/9/2005 9:47:50 AM, Burhan Khalid (phplist@xxxxxxxxxxxx) wrote:
> Ryan A wrote:
>
> > <clip>
>
> > Your looking at something like. For ages between 21 and 23
>
> >
>
> > $Upper = date("m-d-Y", mktime(0,0,0,date("m"),date("d"),date("y")-22));
>
> > $Lower = date("m-d-Y", mktime(0,0,0,date("m"),date("d"),date("y")-23));
>
> >
>
> > $sql =
> "SELECT field1,field2,field3 FROM `table_name` WHERE `age`
> > BETWEEN " .
> $Lower . " AND " . $Upper;
>
> >
>
> > $result = myqsl_query($sql);
>
> >
>
> > etc....
>
> >
>
> > Cheers
>
> > Richard
>
> > </clip>
>
> If you are lucky enough to use MySQL 5 *grin* you can simply do :
>
> SELECT field1,field2 FROM `sometable` WHERE
> TIMESTAMPDIFF(YEAR,NOW(),`age`) = 22
>
> to find all 22 year olds.
Hey,
Luck and me? You dont know who you are talking to my friend....I am still on
mysql 3.23 not even
4.1 !!!
:-D
Cheers,
Ryan
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