Hey,
This is a common mistake...have a look at what you wrote:
>if ($n=$Pagenum) {print ' <strong> ' . $n;}
take a look again....see the problem?
The above will always validate to true...reason being...you gotto use the
equal to equal to instead of just equal to...like this:
if ($n==$Pagenum) {print ' <strong> ' . $n;}
Hope that helped.
Cheers,
Ryan
On 4/25/2005 6:40:24 PM, Ed Dorsch (edorsch@xxxxxxxxxxx) wrote:
> Thanks Ryan!
>
>
>
> I'm having a difficult time, though, with the exact syntax. And where,
exactly, to nest the If > then. I tried this, but it didn't
> work. Nothing displayed and I think it got caught in an endless loop:
>
>
>
> $max=20;
>
> $max++;
>
> for ($n = 1; $n < $max; $n++)
>
>
>
> if ($n=$Pagenum) {print ' <strong> ' . $n;}
>
>
>
> else
>
>
>
> {print ' <a href="pag_gallery.php?Pagenum='.$n.'"'.'>'.$n.'</a>';}
>
> print ' <br><br>';
>
>
>
>
>
>
>
> -----Original Message-----
>
> From: Ryan A [mailto:ryan@xxxxxxxxxxxx]
>
> Sent: Monday, April 25, 2005 8:47 AM
>
> To: Ed Dorsch
>
> Cc: php
>
> Subject: Re: link generating script
>
>
>
>
>
>
>
> On 4/25/2005 5:23:16 PM, Ed Dorsch (edorsch@xxxxxxxxxxx) wrote:
>
> >
> I'm scripting a photo gallery page that generates links (1 through $max),
> sends the selected number in the url, then displays a set of photos based
on
> the number. However, I want it to display the number of the current
gallery
> diffe
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