From: Mike Johnson [mailto:mike@xxxxxxxxxxxxxxxxx] > From: PartyPosters [mailto:sales@xxxxxxxxxxxxxxxxxx] > > > Hello, > > I have a variable that contains a filename, I want to be able > > to insert the date and time just before for the ".jpg" > > for example if my filename is 'pic.jpg' I want it to read > > 'pic_Monday 15th of January 2003 05:51:38 AM.jpg (or if > > anyone else knowshow to write the time and time all in > > numbers it would be appreciated as I'm using ate("l dS of F Y > > h:i:s A") which obviously is a bit long. > > First off, I'd probably use preg_replace(). Maybe something like: > > $pattern = '/^(.*?)(\.jpg)$/'; > $replacement = '\1' . date('l dS of F Y h:i:s A') . '\2'; > $filename = preg_replace($pattern, $replacement, $filename); > > I haven't tested that, but I think it should work. Actually, it occurs to me that strrpos() might be faster. $filename = substr($filename, 0, strrpos('.jpg')) . date('YmdHis') . substr($filename, strrpos('.jpg'), strlen($filename)); Might need to tweak it, but that should work. -- Mike Johnson Smarter Living, Inc. Web Developer www.smartertravel.com mike@xxxxxxxxxxxxxxxxx (617) 886-5539 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
