Hi, I am trying to execute one application (bat file) and need to pass parameter to it. I want to put this into wrapper file which i can call over http. Can i do this? I tried the following: ------------------------------------------------------------------ 1) $output = shell_exec('..\phpunit.bat C:\Run.php'); echo $output; Result: No output. Nothing happened. 2) $cmd = '..\..\phpunit.bat'; // Setup an array of arguments to be sent. $arg[] = "..\..\Run.php"; // Pick a place for the temp_file to be placed. $outputfile = '..\..\CMDOUT.txt'; // Setup the command to run from "run" $cmdline = "cmd /C $cmd " . implode(' ', $arg) ; try { echo "Came in try"; $WshShell = new COM("WScript.Shell"); $oExec = $WshShell->Run($cmdline, 3, true); echo $oExec; // This is not getting printed. echo "Coming out of try"; } catch(Exception $e) { echo "came in catch"; print("Caught Exception in " . $e->file() . " on line " . $e->line() . "<br>\n"); } Result: Nothing is happening. It is printing both the statements in the try block. 3) $firstArg = "C:\\..\\..\\Run.php"; $output = exec("C:\\..\\..\\phpunit.bat $firstArg"); Result: Still nothing is happening. 4)$output = exec("C:\\..\\..\\phpunit.bat $firstArg 2>&1", $myOut); echo "<br/>My out value is ".$myOut; Result: My out value is Array operable program or batch file. -------------------------------------------------------------- All the above approaches not working for me. Can somebody inform me where i need to make changes. Thanks in advance. Regards, Dipesh