On Mon, 2005-03-14 at 18:07, Phil Neeb wrote: > Greets, > I'm running into the problem of not having a server that gives me database > access or ability to use files to store my data ... Yeah, I know, it sucks. > Anyway ... My page has a number of profiles about people involved with my > organization and all the profiles load into a set appearance. I have all > the information about each person stored in individual arrays (if there's an > easier way to do this w/o database or files, I'd love to hear it) ... > anyway, I pass a variable through the URL which causes the array info to > load, but I use an if statement for EVERYONE which makes my work way too > tedious ... The variable I pass is the same value as the name each person's > array (the variable is stored in the link) so, I'm curious if there's a way > I can use the variable as the array name and cut out those tons of if > statements. if( isset( $$person ) ) { $profile = $$person; } Where the value of $person is a string that corresponds to the profile array name you wish to access. Cheers, Rob. -- .------------------------------------------------------------. | InterJinn Application Framework - http://www.interjinn.com | :------------------------------------------------------------: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `------------------------------------------------------------' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php