Hi, Saturday, March 5, 2005, 12:38:20 AM, you wrote: BS> Hello. BS> How do i print a line return using the echo command, for when i see the BS> page source, BS> i get the code line by line and not all in the same line. BS> using double quotes ( " ), i can put \n at the end and i get the result BS> i want, BS> but, using sinle quotes ( ' ), \n doesnt work. BS> if i use double quotes, in a simple html comand i need to use \" and i BS> dont want that. BS> is any way i could use single quotes, and getting the line feed ?? BS> example: BS> Double quotes: BS> echo "<table border=\"1\" width=\"800px\">\n"; BS> single quotes: BS> echo '<table border="1" width="800px">'; BS> cheers BS> Bruno Santos BS> -- BS> Say no to software patents BS> www.nosoftwarepatents.com/ BS> -- BS> bvsantos@xxxxxxxxxxxxxxxx BS> -- BS> Divisao de Informatica BS> informatica@xxxxxxxxxxxxxxxx BS> Tel: +351 272 000 155 BS> Fax: +351 272 000 257 BS> -- BS> Hospital Amato Lusitano BS> geral@xxxxxxxxxxxxxxxx BS> Tel: +351 272 000 272 BS> Fax: +351 272 000 257 you could do: define('LF',"\n"); echo '<table border="1">'.LF; -- regards, Tom -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php