anirudh dutt wrote:
On Fri, 4 Mar 2005 17:41:01 +0800, yangshiqi <yangshiqi@xxxxxxxx> wrote:
class DebugHelper
{
var $_str;
function do($string)
(
//here I want to know which class called this function do to
trace the bug.
$this->_str .= $string;
)
function show()
{
return $this->_str;
}
}
class B
{
function B()
{
$debug = &new DebugHelper;
$debug->do('here');
...
}
}
create a debug function (public) and use get_class. call that in the
if you are using the 'public' keyword then you have to use php5,.....
debug function. when u want to do the debugging, use it with the obj
as parameter, maybe $this will work when u're in the class, otherwise,
use the object aka class instance variable.
u may wanna pass by reference and make it const (won't have to use
if you're using php5 all objects are references, pass-by-reference occurs
whether you like it or not (unless you specifically use 'clone')
...also a constant (global or class scope) cannot be set to an object.
I'm still very curious as to how Yangshiqi intends to use his DebugHelper class!
(apologies if I have written your name incorrectly.)
more memory for it...since it's task with it is small and read-only)
from http://php.net/get_class
[quote]
Example 1. Using get_class()
<?php
class foo {
function foo()
{
// implements some logic
}
function name()
{
echo "My name is " , get_class($this) , "\n";
}
}
// create an object
$bar = new foo();
// external call
echo "Its name is " , get_class($bar) , "\n";
// internal call
$bar->name();
?>
The above example will output:
Its name is foo
My name is foo
[/quote]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
