dunno if u've read the options ppl have given u or u've ignored their answers: imho, these are the answers to ur question: On Sat, 26 Feb 2005 00:46:36 +0100, rich <richgray@xxxxxxxxx> wrote: > > is this what you're after? > > $this = ($something ? $that : $this) > > rich > On Fri, 25 Feb 2005 17:35:03 -0800, Chris W. Parker <cparker@xxxxxxxxxxxx> wrote: > Jason Barnett <mailto:jason.barnett@xxxxxxxxxxxxx> > on Friday, February 25, 2005 2:10 PM said: > > > $this = $something ? $that : null; > > That won't work because I'm setting a default value for $this and want > it to change only if it has to. The long winded way to write this would > be: > > <?php > > $myVariable = "default"; > > if($somethingElse == "a value") > { > $myVariable = "new value"; > } > else > { > // don't do anything > } > > ?> > > Chris. > so this one still applies: On Sat, 26 Feb 2005 01:03:51 +0100, Jochem Maas <jochem@xxxxxxxxxxxxx> wrote: > or one of these might work for you; > > $this = ($something) ? $that: $this; // if $this already exists. > > or > > $this = ($something) ? $that: null; // if $this does not exist and your happy to use is_null() > to put it simply, use: $this = ($something ? $that : $this) it does have the else part of the ternary operator, but it's the closest. it assumes that 'this' has a value it already should have and unless the condition 'something' is true, the value remains the same (or remains null/not set). in which case... On Mon, 28 Feb 2005 17:12:15 -0800 (PST), Richard Lynch <ceo@xxxxxxxxx> wrote: > If you're not *SURE* $this has a value: > > $this = ($something ? $that : (isset($this) ? $this : NULL)); > u've also mentioned: On Fri, 25 Feb 2005 17:28:13 -0800, Chris W. Parker <cparker@xxxxxxxxxxxx> wrote: > Justin Lilly <mailto:justinlilly@xxxxxxxxx> > on Friday, February 25, 2005 3:10 PM said: > > > This should do the trick: > > > > $something ? $this=$that > > Actually that gives a synax error. But I've figured it out based on your > suggestion. > > It's actually: > > <?php > > $something && $this = $that; > > ?> this seems to do the trick as per "Like ternary but without the else". for those who want to know, u can even use: $a && print "this only prints if 'a' is non false" but not echo since it doesn't return a value. <?php $b = 2; $a = !true; $a && $b = 5; $a && print "$a, $b (boolean-in-a-line worked)<br>\n"; echo "$a, $b :: echo line"; ?> u get either: 1, 5 (boolean-in-a-line worked) 1, 5 :: echo line - OR - , 2 :: echo line depending on combos with $a = true or $a = !true. true prints as 1. so u've found ur answer. -- ]# Anirudh Dutt ...pilot of the storm who leaves no trace like thoughts inside a dream -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
