Well.. i just got done doing something like what you are trying to
accomplish... you will need to name your check boxes like so :
name="completed[]"
when the form is submitted, I use something like this and shove it
into a field in the database:
if($_POST['completed'] <> NULL)
{
// This makes one string of all the check boxes
$completed_separated = implode(":", $_POST['completed']);
}
else
{
$comma_separated = NULL;
}
anyhow... use explode to get thte values out... not sure how you are
using this... but i made each check box equal to a value when checked
i.e. 23, 34
so, not sure if this is the right way to do it, but i find it to be a
pretty simple solution for my uses.
cheers
On Fri, 21 Jan 2005 16:47:11 -0500, Hutchins, Richard
<Richard.Hutchins@xxxxxxxxxxxxxx> wrote:
> You can't just echo out an array. You have to either use print_r() or
> iterate over it with a while or for...next loop. But if you just want to see
> what's in the array, print_r() it.
>
> As to why it doesn't bring over the other checkboxes...
>
> If you have (pseudocode)
> <html>
> <form name="myform" method="post" action="myupdate.php">
> <input type="checkbox" name="completed[]" value="value1"> Checkbox 1
> <input type="checkbox" name="completed[]" value="value2"> Checkbox 2
> <input type="checkbox" name="completed[]" value="value3"> Checkbox 3
> </form>
> </html>
>
> And you check the first two checkboxes, then the resulting array will be
> (pseudocode again):
> completed(value1,value2)
>
> And from there, you just access the array contents as you would with any
> other multidimensional array.
>
> If you don't check anything on the page, then the array will be empty and, I
> think, won't even be sent in the $_POST array. I'm sure somebody will
> correct me there if my memory has failed me.
>
> -----Original Message-----
> From: Craig Hoffman [mailto:choffman@xxxxxxxxxx]
> Sent: Friday, January 21, 2005 4:32 PM
> To: php-db@xxxxxxxxxxxxx
> Cc: Richard Hutchins
> Subject: Re: [PHP-DB] checkboxes
>
> I've tried that and it still doesn't bring over the other checkboxes
> that have been checked. Plus when I echo it out I get
> Array instead of the variable name.
>
> On Jan 21, 2005, at 3:14 PM, Hutchins, Richard wrote:
>
> > Probably all you need to do is name your checkboxes as an array thusly:
> >
> > name="completed[]"
> >
> > Then you can access the array on your update page and do whatever you
> > wish
> > with it.
> >
> > Hope this helps.
> >
> > Rich
> >
> > -----Original Message-----
> > From: Craig Hoffman [mailto:choffman@xxxxxxxxxx]
> > Sent: Friday, January 21, 2005 4:03 PM
> > To: php-db@xxxxxxxxxxxxx
> > Subject: [PHP-DB] checkboxes
> >
> >
> > I have a form that display's a checkbox if the value is NULL. The form
> > is in a do... while loop, so the user may check multiple checkboxes.
> > I am trying to pass the variable of each checkboxes to an update
> > statement in MySQL. THe problem is I am only getting one of the
> > checkboxes, even if all of them are checked. Here is my code block,
> > any help would be great. - Craig
> >
> > //From form page
> > <form>
> > <input type='checkbox' name='completed' value='Done' >
> > </form>
> >
> > //MySQL Update Page
> > $email = $_POST['email'] == $route;
> > $completed = $_POST["completed"] == $route;
> > $route_name = trim($_POST["route_name"]) == $route;
> > $user_id = $_POST['user_id'] == $route;
> > $id = $_POST['id'] == $route;
> >
> > $route = array(id => "$_POST[id]", completed => "$_POST[completed]",
> > route_name => "$_POST[route_name]", user_id => "$_POST[user_id]");
> >
> > foreach ($route as $key => $values) {
> > echo("<br />");
> > echo $values;
> > //MySQL Update statement will go here.
> > }
> >
> > --
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