"John Taylor-Johnston" <taylorjo@xxxxxxxxxxxxxxxxxxxxxxx> wrote in message news:41E9A649.83A9984C@xxxxxxxxxxxxxxxxxxxxxxxxxx > I might be doing this backwards, but how do I extract the date from $week5 and display $week5 + 4 days. I would like to create a function so when I pass > > echo displaydate($week5); > > it echos "February 14-18" > > $week0 = "2005-01-10"; > $week1 = "2005-01-17"; > $week2 = "2005-01-24"; > $week3 = "2005-01-31"; > $week4 = "2005-02-07"; > $week5 = "2005-02-14"; > $week6 = "2005-02-21"; > $week7 = "2005-02-28"; > > `Doable´? Easy enough to learn how to do? > > John Hi John, // convert your data to a timestamp: $firstDayTs = strtotime($week5); // add 4 days $lastDayTs = $firstDayTs + (4 * 86400); echo date('F', $firstDayTs) . ' ' . date('m', $firstDayTs) . '-' . date('m', $lastDayTs); Not tested. Maybe there's an easier way to do this. Regards, Torsten Roehr -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
