Wil Hitchman wrote:
I get the following error
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wilmail/public_html/elblog.php on line 7
&n=& //error ends here
with the following bit of code
$qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC");
$nRows = mysql_num_rows($qResult);
$rString ="&n=".$nRows;
If I am just naming a variable how is the argument not valid?
Thanks,
Wil
Echo out mysql_error() after you execute mysql_query()
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John C. Nichel
ÜberGeek
KegWorks.com
716.856.9675
john@xxxxxxxxxxxx
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