Re: making FORM dissapear when successful login

JHollis <jhollis@xxxxxxxxx> · Wed, 05 Jan 2005 22:49:10 -0500

Where do i need to start my session?  Ive copied and pasted exactly what 
you have typed..and the form doesnt display unless i hard code the 
variable to "NO".

Jerry Kita wrote:
I do exactly the same thing on my website. I use PHP's Session handling 
to determine if a user is actually logged on.

You can see that I check a variable called $validlogon which I set to 
either YES or NO at the beginning of the script

<?php
if ($validlogon == "NO") {
print "<p class=\"hnavbar\">Salkehatchie Members Login Here:<br>\n";
print "<form action=\"Salkehatchie_LoginScript.php\" method=\"POST\">\n";
print "<p class=\"login\"><small>USER ID:</small><br>\n";
print "<input type=\"text\" name=\"userid\"><br><br>\n";
print "<small>PASSWORD:</small><br>\n";
print "<input type=\"password\" name=\"password\"><br><br>\n";
print "<input type=\"submit\" value=\"Enter\"></p>\n";
print "</form>\n";
                          }
?>

Near the beginning of my script I check for the existence of a valid 
session

<?php
if (isset($_SESSION[userid])) {
   $validlogon = "YES";
   } else {
   $validlogon = "NO";
   }
?>

Setting the $validlogon variable allows me to do a number of useful 
things. For example, there are certain parts of the webpage that I 
reveal to logged in users. Checking $validlogon allows me to decide 
dynamically what to render to the browser. In the following I display

a message showing the user as being logged in and give them a link that

logs them out.

if ($validlogon == "YES") {

   print "<table style=\"width: 100%\";>\n";

   print "<tbody>\n";

   print "<tr>\n";

   print "<td width=\"50%\"><p class=\"login\"><small><b>YOU ARE LOGGED 
    IN AS: $_SESSION[userid]</b></small></p></td>\n";

   print "<td width=\"50%\"><p class=\"login\"><small><b>CLICK <a 
href=\"LogoutScript.php\"> here</a> TO LOGOUT</b></small></p></td>\n";

            print "</tr>\n";

            print "</table>\n";

            }

Hope this is helpful

Jerry Kita

JHollis wrote:

I had this code working the way i wanted it to (as far as correct 
username and password allowing successful login)...but what i want to 
happen now is when a user successfully logs it it will make the login 
form disappear and just say successfully logged in or welcome user and 
a link below it so they can log off and make the form re-appear.  
Below is the code that i have where i tried to get it to disappear on 
successful login, but it stays disappeared all the time.  Can someone 
please point out what im doing wrong.  I have tried everything i can 
think of...and nothing works.  Im a PHP newbie...so im sure some of 
you might get a laugh out of this...if it is real easy.

<---snippet

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" 
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>

<html>

<head>

<link href="style.css" rel="stylesheet" type="text/css" />

</head>

<body>

 <div id="container">

<div id="top">

<h1>header</h1>

</div>
<div id="leftnav">
<p>

    <?php

    $username=$_POST['username'];

    $password=$_POST['password'];

    $db="user";

    $server="localhost";

    $db_username="root";

    $db_password="*******";

        $connect = mysql_connect($server,$db_username,$db_password);

    if (!$connect) {

            die ("could not connect to database");

                    }

    $select = mysql_select_db($db,$connect);

    if (!$select) {

            die ("could not select database $db");

                    }

 /*username='$username'";*/

    $sql = "SELECT * FROM passwords, user_info where id=PID and 
username='$username'";

    $result = mysql_query($sql);

/*$num_rows = mysql_num_rows($result);*/

    while ($user = mysql_fetch_array($result))

        {

        $id = $user['id'];

        $username2 = $user['username'];

        $password2 = $user['password'];

        $firstname = $user['firstname'];

        $email = $user['email_address'];

                  IF ($username=="$username2" && $password=="$password2")

        {

        echo("\"Welcome, <b>$firstname</b>\"");?><br><?

        echo ("\"Your email address is <b>$email<b>\"");?></td><tr>

        <a 
href="<?$_SERVER['PHP_SELF']?>?username=""&?password=""">Logoff</a><?

        break;

        }

        else

        {

        ?>

                <FORM action="<?$_SERVER['PHP_SELF']?>" method="post">

                <INPUT type="hidden" name="id">

                <table>

                <td><b>*</b>Username:</td> <td><INPUT class="input" 
size="8" type="text" name="username" value="<?echo $username?>"></td><tr>

                <td><b>*</b>Password:</td> <td><INPUT class="input" 
size="8" type="password" name="password"></td><tr>

                <td class="xsmall"><b>* Case Sensitive</b></td>

                <td><INPUT type="submit" value="Login"></td><tr>

                <td>&nbsp </td>

                </table>

                </FORM>

                <?

               break;

            }

           }   //IF ($username != $username2 || $password != 
$password2) {//

    ?><br>

    <?

    if  ($username == "" && $password == "") {

        echo ("Please type in a Username and Password");}

    if  ($username != "" && $password == "") {
        echo ("Please type in a password");}

    if  ($username == "" && $password != "") {

        echo ("Please type in a username and password");}

         ?>

                           </p>

</div>

<?if (($username2==$username && $password2==$password) && 
($username2!="" || $password2!="")){?>

<div id="rightnav" class="box">

<p>

</p>

</div>

<?}?>

<div id="content">

<h2>Subheading</h2>

<p>

</p>

<p>

</p>

</div>

<div id="footer">

<p>

Today is

<?php

    echo( date("F dS Y."));

?>

</p>

</div>

</div>

</body>

</html>

---->snippet

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