Hi Khuram
I use this function
function daysLeft($startDate,$endDate=false){
// convert to timestamps
$start_stamp = strtotime($startDate);
$end_stamp = ($endDate)?strtotime($endDate):time();
if($start_stamp > $end_stamp){
// start date is passed end date
return "0";
}
$difference = $end_stamp - $start_stamp;
return floor($difference/(24*60*60));
}
echo daysleft("today", "01/05/2005");
Note, remeber to use the correct dat format otherwise you will see
some unexpected results.
Jarratt
On Mon, 3 Jan 2005 02:33:58 -0800 (PST), khuram noman
<khuram_noman@xxxxxxxxx> wrote:
> Hi
>
> Is there any function avialable in PHP to calculate
> the no of days by passing 2 dates like 1 argument is
> 1/1/2005 and the second one is 1/2/2005 then it
> returns the no of days or how can i do that if there
> is no builtin function .
>
> Regards
> Khuram Noman
>
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