On Friday 17 December 2004 02:33, Sebastian wrote:
> I cannot solve this problem,. sorry if this looks confusing,.
It is ...
> i have a form and don't want to set the variable if the in_array is true..
> the code works, up until i add the last !$buddy in the statement, for some
> reason it seems to always be true, ... something i'm doing wrong? btw, i
> cannot add the in_array to the statement because if the $buddylist is empty
> it will generate errors because of the empty implode.
>
> $buddylist = preg_split('/( )+/', trim($userinfo['buddylist']), -1,
> PREG_SPLIT_NO_EMPTY);
OK, it looks like $userinfo['buddylist'] is a string containing buddies
separated by some whitespace:
'buddy1 buddy2'
After the above statement $buddylist becomes an array.
> if($buddylist)
> {
> $buddy = in_array($uname['uid'], array(implode(',', $buddylist)));
> }
Here implode() returns a string containing 'buddy1,buddy2', then you stick
that into an array() which is effectively:
array('buddy1,buddy2'); // note that there is only *1* element
Now unless your $uname['uid'] really is literally 'buddy1,buddy2' then $buddy
will be false.
Hope that's enough to get you going.
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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