Richard Kurth wrote: > > I have a stupid question but I can not figure it out > I am using a class that creates the select statement for mysql. > I am ale to add all the data with out any problem. But when I run the > class to get the results. I can only see the results by running echo in > front of the call to the class . > echo $q->getQuery(); > Output SELECT * FROM listing WHERE state='wa' > if I > $q->getQuery(); > echo $g; > Output Object id #1 > How do I use the results in my mysql query If I can not move it to a > variable You are confusing the object itself ($g) with one of its member functions ($g->getQuery()) If you echo $g, you will see only the object itself. If you echo $g->getQuery() you will see the query you built. If you want that query in a variable, you could do: $query = $g->getQuery(); mysql_query($query); You could even do: mysql_query($g->getQuery()); But you wouldn't be able to do: mysql_query($g); because $g isn't a string, it's an object. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
