What is wrong with this code? Why $input_str is empty.
if ($handle = opendir('/home/test2/')) {
echo "Directory handle: $handle\n";
echo "Files:\n";
while (false !== ($file = readdir($handle))) {
if($file != "." && $file != ".."){
$handle1 = fopen($file, "a+");
$input_str = fread($handle1, filesize($file));
echo "TEST".$input_str;
}
}
}
On Sun, 21 Nov 2004 05:40:07 +0800, Jason Wong <php-general@xxxxxxxxxxxx> wrote:
> On Sunday 21 November 2004 05:11, Jerry Swanson wrote:
>
>
> > I know how to read a file. But the problem is different, I have
> > directory that has more than 250 files. I need to read each file and
> > process it. But How I know what file to read?
> > ls -l (show all files). How I can select each file without knowing
> > name? The file will be process and than delete.
>
> To get list of files from directory:
> manual > Directory Functions
>
> To open/read/write/delete files:
> manual > Filesystem Functions
>
> There are plenty of examples in the manual and in the user notes of the online
> manual.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
> ------------------------------------------
> Search the list archives before you post
> http://marc.theaimsgroup.com/?l=php-general
> ------------------------------------------
> /*
> Do not try to solve all life's problems at once -- learn to dread each
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>
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