Hey again :) Peter Lauri: > But what if the array have a unordered keystructure? What your loop do is > to call the value with key $i, or am I wrong? What if the keys are strings? $arr= array(1 => "dirk", 'wife' => "iris", 'dog' => "feivel", 'peter' => "lauri"); $values= array_values($arr); for($i= 0, $size= sizeof($values); $i < $size; $i++) { echo $values[$i]; } should work :) > "Dirk Kredler" <dirk@xxxxxxxxxxxxxxxxx> skrev i meddelandet > news:200411171348.13856.dirk@xxxxxxxxxxxxxxxxxxxx > > > hey :) > > > > i use for this reason: > > > > for($i= 0, $size= sizeof($arr); $i < $size; $i++) { > > echo $arr[$i]; > > } > > > > Peter Lauri: > > > Best groupmember, > > > > > > For the moment when I loop an array I use something like this: > > > > > > reset($arr); > > > while($a=each($arr)) { > > > echo $a['value']; > > > } > > > > > > But the each() function genereates a array with four elements > > (0,1,value, > > > > key), I am only interested in the "value". -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php