Re: calling function from function?

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Rick Fletcher wrote:
db( $defined[0], $defined[1], $defined[2], $defined[3] );


 > which tells me that the $db handle is not being returned when called
 > from the db() function from within the logs() function and I am not
 > sure why?

it's being returned, you've just forgotten to assign it. add a "$db = " to the beginning of that line and you should be good to go.

--Rick
dang, thanks dude I knew it was something simple like that. just goes to show you how over analyzed things are. lol. thanks again.

--
Jason Gerfen
jason.gerfen@xxxxxxxxxxxx

"And remember... If the ladies
 don't find you handsome, they
 should at least find you handy..."
             ~The Red Green show

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