[snip] If I defined a function with 4 parameters but only pass 3 I get an error. Is there anyway around this? I want to be able to set the missing parameter to a default value if it is not passed which works ok but How do I get rid of the error message? [/snip] http://us2.php.net/manual/en/function.func-num-args.php "func_num_args() may be used in conjunction with func_get_arg() and func_get_args() to allow user-defined functions to accept variable-length argument lists. " -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
