intval converts other types to integers. Integers can only be whole numbers, eg 1, 2, 15, -789, etc. No matter what decimals, intval converts it to the lower (closer to 0) integer value. Eg 2.5 => 2, 19.9=>19, -25.3 => -25 etc.Hello.
I have some problems with basic math in the function below.
function Custom_Round($Digit, $Divisor) { return (($Digit / $Divisor) - (($Digit % $Divisor) / $Divisor)); }
Custom_Round(23, 10) returns float(2) as expected. Same for Custom_Round(22, 10).
BUT when you compare the both results like below Custom_Round(23, 10)!=Custom_Round(22, 10) I always get bool(true) whereas the result should be bool(false)
When I have debuged this small piece of code I found out that intval(Custom_Round(23, 10)) = 1
whats definitly not expected.
But intval(Custom_Round(22, 10)) = 2 as expected. Replacing Custom_Round() by Floor() works fine, but why does the custom
function doing the same not work? Is this a bug in PHP?
This problem occurse in PHP 4.3.3 and PHP 5.0.1.
Thanks for help, Christoph
What happens now is that you're converting a float to an integer, float=>integer conversion has a lot of "problems", floating point numbers have a lot more precision. Numbers given as being float(2) can actually be something of the like 1.99999999999999999999999999999999999999, and when converted to intgers, they drop down to 1 instead of 2.
This is explained here: http://www.php.net/manual/en/language.types.integer.php#language.types.integer.casting.from-float
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