Oluwatope Akinniyi wrote: > This > SELECT 1 WHERE '95b5a221aeba15c' IN (E'\'' || replace('95b5a221aeba15c+fb4e7219ab898ce+b08586cb81059f9','+',''',''') || E'\'') returns no row while This returns a string with text '95b...', '...', '...' > SELECT 1 WHERE '95b5a221aeba15c' IN ('95b5a221aeba15c','fb4e7219ab898ce','b08586cb81059f9') returns a row. This is three values. You could either use strpos() on the raw string (as long as you know you won't get partial/multiple matches). OR split the string to an array: SELECT 1 WHERE '95b5a221aeba15c' = ANY( string_to_array( '95b5a221aeba15c+fb4e7219ab898ce+b08586cb81059f9', '+' ) ); -- Richard Huxton Archonet Ltd -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general