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Re: inserting only new rows from csv file

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> -----Original Message-----
> From: pgsql-general-owner@xxxxxxxxxxxxxx
> [mailto:pgsql-general-owner@xxxxxxxxxxxxxx]On Behalf Of Scott Marlowe
> Sent: Thursday, 2 October 2008 7:39 AM
> To: Seb
> Cc: pgsql-general@xxxxxxxxxxxxxx
> Subject: Re: [GENERAL] inserting only new rows from csv file
> 
> 
> On Wed, Oct 1, 2008 at 3:16 PM, Seb <spluque@xxxxxxxxx> wrote:
> > Hi,
> >
> > I've seen some approaches to this problem, but I suspect there are
> > better ways.
> >
> > A csv file is produced nightly, with the same table 
> structure as a table
> > in a PostgreSQL database.  The file grows over time as new 
> records are
> > added every day.  However, the rows in the file may not be 
> sorted the
> > same way every day.
> >
> > I need to isolate the new rows and insert them into the 
> database table.
> > Before I start writing a script to do this, I need to 
> decide whether to
> > do the comparison between the database table and the csv 
> file: a) within
> > the database, or b) COPY'ing the table to a file and then do the
> > comparison.  I'm not very experienced with SQL, so am more 
> comfortable
> > with the latter option using plain shell and awk.  Which 
> route is best?
> > If a), I'd appreciate some SQL code to do it.  Thanks.
> 
> I'd load them into a staging table, and use a query (either a
> subselect or a left join where null type query) to load them into the
> master table.
> 
I solved the same problem this way.
csv file processed by gawk script to produce SQL script with inserts etc. Then pass
the SQL file to psql.

This is what I have in my BEGIN line of my gawk script leaving out appropriate print statements for clarity.

CREATE TEMPORARY TABLE tempjobdetails( LIKE jobdetails INCLUDING DEFAULTS );

--Do load from csv into tempjobdetails

This is in my END line of the gawk scrip ditto the print statements.

insert into jobdetails
   ( select * from tempjobdetails
     where
         ( tempjobdetails.jobnum, tempjobdetails.opnum )
         not in
         ( select
               jobdetails.jobnum, jobdetails.opnum from jobdetails
          )
    );

Hope this helps.

Allan


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