Ow Mun Heng wrote:
Could it be that it's not able to determine the B2.%.SX in there?
explain select count(*) from d_trr_iw where ast_revision like 'B2.P.SX'
even this will result in a seq_scan.
How many values have you got that start with 'B2.'? If it's more than
about 5% then it's probably quicker to sequential scan anyway.
Since the equals query says there's one row with a P in the middle, what
does this say?
explain select count(*) from d_trr_iw where ast_revision like 'B2.P%.SX'
or pick a value that you know can't exist e.g. if ast_revision can never start with WW then
explain select count(*) from d_trr_iw where ast_revision like 'WW.%.SX'
klint.
--
Klint Gore
Database Manager
Sheep CRC
A.G.B.U.
University of New England
Armidale NSW 2350
Ph: 02 6773 3789
Fax: 02 6773 3266
EMail: kgore4@xxxxxxxxxx
