Gurjeet Singh writes:
Thus, writing a pattern that actually matches a literal backslash means writing four backslashes in the statement.
Thanks.select * from mytable where f1 like '%\\\\%'; Worked.
For the archives..After reading section 4.1.2.2 Also found that these other one also works
select * from mytable where f1 ~ $$\\$$; select * from mytable where f1 like $$%\\%$$;