Double holds 15 places which is the highest value of precision it can
maintain before rounding occurs.
Is is limit less no, but what is?
Practically speaking taking a vale 0.000,000,000,000,001 aka
1 trillionth of anything, i view the problem solved for 98% of problems.
Does it hide? Yes, but it hides it very well. :-P
Tomasz Ostrowski wrote:
On 2008-05-13 19:21, Justin wrote:
I change it to double problem goes away.
No, it does not. It only hides it deeper. double is also a floating
point type and has the same problems.
Regards
Tometzky
