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Re: Need efficient way to do comparison with NULL as an option

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Tom Lane wrote:
"D. Dante Lorenso" <dante@xxxxxxxxxxx> writes:
I'm looking for an operator that will compare NULL with NULL and evaluate as TRUE.
regression=# select null IS NOT DISTINCT FROM 42;
?column? ----------
 f
(1 row)
regression=# select null IS NOT DISTINCT FROM null;
?column? ----------
 t
(1 row)
However, if you're expecting this to be real efficient (like, use an
index), you're out of luck ...
If the value I'm comparing is 0, I want it to match the NULL values.
[ raised eyebrow... ]  Sir, you need to rethink your data
representation.

Tom,

I don't understand why my index is not being used (other than you said so):

----------
  SELECT COUNT(*)
  FROM audio
  WHERE (folder_id = ? AND ? IS NOT NULL)
  OR (folder_id IS NULL AND ? IS NULL);

uses index when ? = 100 (as expected)
does NOT use index when ? = NULL (as expected)

----------
  SELECT COUNT(*)
  FROM audio
  WHERE folder_id IS NOT DISTINCT FROM ?;

does NOT use index when ? = NULL (as expected)
does NOT use index when ? = 100 (NOT expected!) <-------------!!!

----------

So, although 'IS NOT DISTINCT FROM' is a lot more readable than my other form, it's apparently not efficient. How can I get the efficiency and still have the clarity?

-- Dante

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