peter pilsl wrote: > But there is a problem now: There are also entries in fn_kat which dont > have corresponding entries in fn_dokumente and this entries should be > listed too. With the proper count=0 !! Your problem is not on the GROUP BY, but rather that you need an outer join. Try something like select k.kategorie,count(d.oid) from fn_kat k left join fn_dokumente d on k.id=d.kategorie group by k.kategorie; -- Alvaro Herrera http://www.PlanetPostgreSQL.org/ "The first of April is the day we remember what we are the other 364 days of the year" (Mark Twain) ---------------------------(end of broadcast)--------------------------- TIP 9: In versions below 8.0, the planner will ignore your desire to choose an index scan if your joining column's datatypes do not match
