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Re: SQL Query

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Hello All:

Ashish wants latest output_date but less than now()

>want to retrieve all the output_id  which are having latest
>output_date but less than now() (no future output_dates)

The query written by Tirnath will return count of all output ids given parent id where output_date is less than now, it won't return rows for latest output_date.

I propose the following solution:

SELECT o.output_id
FROM my_table o, parent_table p
WHERE o.parent_id = p.parent_id
AND o.output_date < now()
AND NOT EXISTS
(
 SELECT out.output_date
 FROM my_table out
 WHERE out.parent_id = o.parent_id
 AND out.output_date < now ()
 AND o.output_date < out.output_date
);

The idea is get first maximum date which is less than now(). Assuming now() as the maximum date, the problem reduces to finding second maximum date.
The nested query means: the date in context (outer query date) shouldn't be less than any date which is less than now().

This will give you the latest output date grouped by parent_id albeit there's no group clause used. :-)

Let me know if there's any mistake.
Cheers,
Ranbeer Makin




On Dec 13, 2007 6:32 PM, Trinath Somanchi <trinaths@xxxxxxxxxx > wrote:
Hi ,

Try this out

SELECT count( o.id)
FROM   output_table o , parent_table p
WHERE  o.pid=p.pid AND o_date < now()
GROUP BY p.pid ;


On Thu, 13 Dec 2007 10:00:56 +0000 (GMT)
Ashish Karalkar < ashish_postgre@xxxxxxxxxxx> wrote:

> Hello List member,
> I have a table which ha sfollowing structure
>
> my_table:
> (
>     output_id serial priimary key,
>     parent_id int,
>     output_date timesatmp
> )
>
> parent_table:
>
> (parent_id int,
> parent desc
> )
>
> the my_table contains data for previous as well as future output
> dates. for single parent there may be multiple rows.
>
> I want to retrieve all the output_id  which are having latest
> output_date but less than now() (no future output_dates) group by
> parent_id
>
> Thanks in advance
>
> With Regards
> Ashish...
>
>
> ---------------------------------
>  Forgot the famous last words? Access your message archive online.
> Click here.

--
Trinath Somanchi ,
(trinaths@xxxxxxxxxx),

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