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Re: pgcrypto functions fail for asymmetric encryption/decryption

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On 12/3/07, Stefan Niantschur <sniantschur@xxxxxx> wrote:
> > Or at least send key parameters (gpg --list-keys output).
>
> pub 1024D/0476AD06 2007-11-27 [verfällt: 2008-11-26]
> uid Test User (Probebenutzer) <test@xxxxxxxxx>
> sub 2048g/879D6C41 2007-11-27 [verfällt: 2008-11-26]

Elgamal 2048 works here, plus it should be tested in buildfarm also.

> > Also I need PostgreSQL version, if its compiled with OpenSSL,
> > then OpenSSL version, your OS and CPU info, just in case.
> > Compiler + compiler options maybe too.
>
> The database system runs on a virtualised box in qemu 0.9.0-14
>
> PostgreSQL version: PostgreSQL 8.2.5 on i686-pc-linux-gnu, compiled
> by GCC gcc (GCC) 4.2.2
>
> compiled with option: --with-openssl
> OpenSSL-version: 0.9.8g
> OS: Archlinux (current)
> CPU: AMD Athlon(tm) 64 Processor 3000+

Could you run regression tests for both pgcrypto and Postgres
itself on your env:

  $ cd pg-8.2.5
  $ make check
  $ cd contrib/pgcrypto
  $ make install installcheck

That should give more reproducible case hopefully.

The "make check" creates its own temp installation but
the pgcrypto's "make installcheck" works on already running
postgres installation.  So main postgres instance should
be running.

> > > SELECT encode(decode((SELECT ens_pubkey FROM
> > > ens_user)::text,'escape'),'escape'::text)::text;
> > > -> returns the public key, => ok
> > >
> > > SELECT armor(dearmor((SELECT ens_pubkey FROM ens_user)::text));
> > > -> returns the key in a different format, => problem
> >
> > You mean it gives fixed header? Both pgcrypto and gpg ignore
> > it anyway, so I did not bother guessing it. But if it really
> > causes problems (doubtful) it can be fixed by looking at data.
>
> The pub-key looks like this:
> -----BEGIN PGP PUBLIC KEY BLOCK-----
> Version: GnuPG v2.0.7 (GNU/Linux)
>
> mQGiBEdMDtkRBACk0FB5oLGW2hI3DAZ+Q15UJmEZC2neK8WWnK+1f2fjtvs4Y7L+
> 3uxQTt2issRN+6P/oD62nQhxNS5QZYeWRxUiP/881aoT2uKJMkMRpf6Uwp/Np+4k
>
>
> The armor/dearmor version looks like this:
> -----BEGIN PGP MESSAGE-----
>
> mQGiBEdMDtkRBACk0FB5oLGW2hI3DAZ+Q15UJmEZC2neK8WWnK+1f2fjtvs4Y7L+3uxQTt2issRN
> +6P/oD62nQhxNS5QZYeWRxUiP/881aoT2uKJMkMRpf6Uwp/Np+4k1gIyssWkic1GwPYjk+uXiDMP


Is the following part really missing:

XXXX
-----END PGP MESSAGE-----

???

That would be indeed broken output.  Did you paste rest of the
output intact?  The lengths differ for some reason.  Weird.

> > SELECT
> > >
> armor(pgp_pub_encrypt_bytea(armor(pgp_sym_encrypt('geheim'::text,'test'::text))::bytea,dearmor((SELECT
> > > ens_pubkey FROM ens_user WHERE ens_userid = 10112)::text)));
> > > -> returns a pgp-encrypted message which cannot be decrypted by
> > > GnuPG, => problem
> >
> > This query does not parse, but if I remove the bytea case it works.
>
> At my side both versions work pgp_pub_encrypt and
> pgp_pub_encrypt_bytea. The only thing is that a cast to bytea has to be
> prepare beforehand for the pgp_pub_encrypt_bytea:
> CREATE CAST (BYTEA AS TEXT) WITHOUT function;

Ah, ok.  But why do you need to use the _bytea version?

> The public/private keys should match, as I can encrypt/decrypt the
> message using gpg alone. Inserting the data into a table and using
> pgcrypto functions fail.
>
> No matter whether I try to encrypt a message in postgres and decrypt it
> again in gnupg or the other way round, I always end in an error
> message.

I really would like to know if the regtests pass on your box or not.

If not please send 'regression.diffs' to me.  I'm interested
what exactly fails.

-- 
marko

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