Re: how to generate a list of distinct scalar values from a column which type is array

[David Fetter <david@xxxxxxxxxx>]

On Thu, Feb 22, 2007 at 12:38:50PM +0100, Sergio Andreozzi wrote:
> Dear all,
> 
> given a column which type is for instance varchar(20)[],

This is almost never a good design.  If you must have an interface
like that, make it VIEW over an aggregate, which you can make
writeable.

> is it possible via SQL to generate the list of distinct scalar
> values?

Yes, but you should fix your design :)

CREATE TABLE foo (ft TEXT[]);

COPY foo(ft) FROM stdin;
{aaa,bb,c}
{dddd,eeee}
{aaa,eeee}
\.

SELECT DISTINCT ft[i]
FROM (
    SELECT ft,
        generate_series(
            array_lower(ft,1),
            array_upper(ft,1)
        ) AS i
    FROM foo
) AS bar;

So, yes, you can do it, and no, you shouldn't.

Cheers,
D
-- 
David Fetter <david@xxxxxxxxxx> http://fetter.org/
phone: +1 415 235 3778        AIM: dfetter666
                              Skype: davidfetter

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