On 15/07/2006, at 2:07 AM, Sergio Duran wrote: How about if we make it simpler, only 1 table
create table worker(
name varchar(50),
position varchar(50),
startdate date,
salary numeric(9,2));
insert into worker values ('Jon', 'boss', '2001-01-1', 1000.00);
insert into worker values ('Peter', 'cleaning', '2002-01-01', 100.00);
insert into worker values ('Peter', 'programming', '2004-01-01', 300.00);
insert into worker values ('Peter', 'management', '2006-01-01', 500.00);
select * from worker;
name | position | startdate | salary
-------+-------------+------------+---------
Jon | boss | 2001-01-01 | 1000.00
Peter | cleaning | 2002-01-01 | 100.00
Peter | programming | 2004-01-01 | 300.00
Peter | management | 2006-01-01 | 500.00
I want to group by name, order by date desc and show the first grouped salary, maybe I should write an aggregate function that saves the first value and ignores the next ones. Is there already an aggregate function that does this? I havent written any aggregate functions yet, can anybody spare some pointers?
Try this:
SELECT w2.* FROM ( SELECT name, MAX(startdate) AS startdate FROM worker GROUP BY name ) AS w1 JOIN worker AS w2 ON (w1.name = w2.name AND w1.startdate = w2.startdate);
Obviously you would use a real primary key instead of 'name' for the join constraint but you get the idea
-- Seeya...Q
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