# badlydrawnbhoy@xxxxxxxxx / 2006-06-02 05:18:08 -0700:
> I think I need to explain a bit further.
>
> I tried simply using
>
> update people
> replace(address, 'mailto:','');
>
> but unfortunately that produced a duplicate key error as some of the
> addresses prefixed with 'mailto:' are already present (unprefixed) in
> the table.
>
> So what I need to do is find those entries - those items in the table
> for which there is an equivalent entry prefixed with 'mailto:'.
>
> Sorry if I'm not being very clear!
Not unclear, this question is a completely different animal.
Pick one:
SELECT p.*
FROM people p,
(SELECT REPLACE(address, 'mailto:', '') AS stripped
FROM people
WHERE address LIKE 'mailto:%') AS m
WHERE p.address = m.stripped;
SELECT *
FROM people p
WHERE p.address IN (
SELECT REPLACE(address, 'mailto:', '') AS stripped
FROM people
WHERE address LIKE 'mailto:%');
--
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You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
