Tony Caduto schrieb:
> select array_to_string(conkey,',') from pg_constraint where contype =
> 'p' and conrelid = 17059
>
> returns a value of 1,2,18 for the array to string function,
>
> when I do this it does not return true:
>
> select case when 18 in (array_to_string(conkey,',')) then true else
> false end from pg_constraint where contype = 'p' and conrelid = 17059
When you try:
SELECT (array_to_string(conkey,',')); You will see
why. It basically produces:
('1,2,18') which isnt by far equivalent to (1,2,18)
> but this one does return true
>
> select case when 18 in (1,2,18) then true else false end from
> pg_constraint where contype = 'p' and conrelid = 17059
>
> How come the function does not work in the IN statement? I tried
> casting it to a varchar, but that did not work either.
Its all horribly wrong ;)
1.) Try to avoid arrays in favour of real tables - queries are
easy and fast
2.) if you cant avoid, try WHERE 18 ANY conkey; or the like.
Look up the documentation for real syntax. Dont mix
text/char/varchar with what you type.
HTH
Tino
