On Oct 24, 2005, at 11:27 AM, Johan Wehtje wrote:
This is probably obvious but I am not seeing what is going wrong
with this function definition:
CREATE OR REPLACE FUNCTION "public"."cproc_hli" (bgtemp NUMERIC,
humidity NUMERIC, wspeed NUMERIC) RETURNS NUMERIC AS
IF ($1 < 25)
THEN
SELECT (10.66 * (0.28 * $2)+(1.3 * $1) - $3)
ELSE
SELECT (8.62 * (0.38 * $2) + (1.55 * $1) - (0.5 * $3) + (exp(- $3 +
2.4)))
END IF
LANGUAGE 'plpgsql' VOLATILE RETURNS NULL ON NULL INPUT SECURITY
INVOKER;
ERROR: syntax error at or near "IF" at character 119
LINE 2: IF ($1 < 25)
I have tried with dollar quoting around the function body, changing
the maguage to sql and using CASE ... WHEN instead of IF , tried
Brackets and no brackets around the Boolean expression.. and a
number of other variations, as well as rereading the Documentation.
I have also tried not having aliases/names for the arguments.
In every case I always get the syntax error directly after "AS".
Can somebody point what is probably obvious.
Cheers
Johan Wehtje
This version will compile, but it won't do anything useful:
CREATE OR REPLACE FUNCTION "public"."cproc_hli" (bgtemp NUMERIC,
humidity NUMERIC, wspeed NUMERIC) RETURNS NUMERIC AS $$
BEGIN
IF (bgtemp < 25) THEN
PERFORM (10.66 * (0.28 * humidity)+(1.3 * bgtemp) - wspeed);
ELSE
PERFORM (8.62 * (0.38 * humidity) + (1.55 * bgtemp) - (0.5 * wspeed)
+ (exp(- wspeed + 2.4)));
END IF;
END;
$$ LANGUAGE 'plpgsql' VOLATILE RETURNS NULL ON NULL INPUT SECURITY
INVOKER;
You were missing some basic syntactic requirements, including a BEGIN/
END block, as well as several semicolons. You will also need to
SELECT into a variable if you want anything useful to happen with the
results. I've replaced your SELECTs with PERFORMs to recreate your
function as originally written.
I recommend a closer reading of the chapter on PL/pgSQL:
http://www.postgresql.org/docs/8.0/static/plpgsql.html
--
Thomas F. O'Connell
Co-Founder, Information Architect
Sitening, LLC
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