Each row have a PK (gdid) that will uniquely refrence 50 k/v pair set
On Mon, 23 Dec 2024, 10:35 pm Ron Johnson, <ronljohnsonjr@xxxxxxxxx> wrote:
How do you uniquely reference each set of 50 k/v pairs?On Mon, Dec 23, 2024 at 12:01 PM Divyansh Gupta JNsThMAudy <ag1567827@xxxxxxxxx> wrote:Sure , for example, I have 50 key with name as t1 , t2 ,t3 .......t50
Now each key could have values from 0 to 3
So let suppose we have JSONB like that for row r1
{
t1: 1
t2: 2
t3 : 3
}
As if I convert it into columns so r1 will have
t1 column will contain 1
t2 column will contain 2
...... So on
So here my question is considering one JSONB column is perfect or considering 50 columns will be more optimised.
On Mon, 23 Dec 2024, 10:24 pm Adrian Klaver, <adrian.klaver@xxxxxxxxxxx> wrote:On 12/23/24 08:46, Divyansh Gupta JNsThMAudy wrote:
> Also as you ask how 50 pairs turns into 50 column so each column will be
> a key and the value of that key will store inside their respective
> column for each row
My problem with understanding this is 50 pairs = 100 values, I don't
understand how that can fit in 50 columns that can only handle 1 value
each. You need to provide some example data showing what you want to
achieve. It does not need to be the full 50, just something to show the
process.
>
>
> On Mon, 23 Dec 2024, 10:14 pm Divyansh Gupta JNsThMAudy,
> <ag1567827@xxxxxxxxx <mailto:ag1567827@xxxxxxxxx>> wrote:
>
> As per the discussion with other team members they suggested if we
> store 50 values for keys in an individual column that will provide
> better performance as the data type is native (INT2) on the other
> hand if we store all the key value pair in a single JSONB column the
> performance will degrade even after applying a GIN index on that
> however the statement sounds funny but I want to take everyone openion?
>
>
> On Mon, 23 Dec 2024, 10:05 pm Adrian Klaver,
> <adrian.klaver@xxxxxxxxxxx <mailto:adrian.klaver@xxxxxxxxxxx>> wrote:
>
> On 12/23/24 07:53, Divyansh Gupta JNsThMAudy wrote:
> > Hii Community,
> >
> > I need to provide a support for some functionality for my
> application
> > for that I need to store 50 key value pair set, so I am in a
> dilemma,
> > weather I create 50 new columns of int2 data type each column
> will
>
> This is unclear, I am trying to figure out you go from '50 key
> value
> pair set' to '50 new columns of int2'.
>
> In other words how 50 pairs turn into 50 columns?
>
> Then there is the question of why 50 keys per row in the first
> place?
>
>
> > contain value of a specific key or should I go with JSONB
> data type with
> > 50 key value pair, the table on which I am going to do that
> all contains
> > 1 Billion rows of data and have 84 hash partitions, I have
> gone through
> > multiple articles some of them mentioned it's a good approach
> to create
> > 50 new columns and some states that creating one JSONB would
> be best
> > that's why I need your help to move forward, also I am ready
> to make
> > H-Store instead of JSONB if it provides better performance.
> > Please help me to comes out from that dilemma.
> >
> > Regards,
> > Divyansh Gupta,
> > Database Administrator
>
> --
> Adrian Klaver
> adrian.klaver@xxxxxxxxxxx <mailto:adrian.klaver@xxxxxxxxxxx>
>
--
Adrian Klaver
adrian.klaver@xxxxxxxxxxx
--Death to <Redacted>, and butter sauce.Don't boil me, I'm still alive.<Redacted> lobster!
