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RE: Removing the default grant of EXECUTE on functions/procedures to PUBLIC

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I apologize, that was sloppy.

I was using the acldefault() function with pg_roles, like this:

=> select rolname,  acldefault('f',oid) from pg_roles where rolname like 'mjt%' order by 1;

  rolname  |              acldefault

-----------+--------------------------------------

mjt_test1 | {=X/mjt_test1,mjt_test1=X/mjt_test1}

mjt_test2 | {=X/mjt_test2,mjt_test2=X/mjt_test2}

(2 rows)

 

I had issued

alter default privileges for role mjt_test1 revoke execute on functions from public;

but had not done a similar ALTER for mjt_test2. And so I was surprised that they both showed a default =X/rolename.

 

Examining  \ddp and its underlying quuery, I see that view column pg_default_acl gets a new row with defaclacl populated after the ALTER DEFAULT PRIVILEGES.

 

Thanks very much for your guidance, I am on track now.

 

Mike Tefft

 

From: Tom Lane <tgl@xxxxxxxxxxxxx>
Sent: Friday, July 5, 2024 2:22 PM
To: Tefft, Michael J <Michael.J.Tefft@xxxxxxxxxx>
Cc: pgsql-general@xxxxxxxxxxxxxxxxxxxx
Subject: Re: Removing the default grant of EXECUTE on functions/procedures to PUBLIC

 

"Tefft, Michael J" <Michael.J.Tefft@snapon.com> writes: > I was checking pg_roles.acl_default to see if my role-level ALTER DEFAULT PRIVILEGES had been effective. But I see the same content both before and after the ALTEr. Er, what?

"Tefft, Michael J" <Michael.J.Tefft@xxxxxxxxxx> writes:
> I was checking pg_roles.acl_default to see if my role-level ALTER DEFAULT PRIVILEGES had been effective. But I see the same content both before and after the ALTEr.
 
Er, what?  There's no column named acl_default in pg_roles, nor any
other standard PG view.
 
psql's "\ddp" command is the most usual way to examine current
defaults:
 
regression=# create user joe;
CREATE ROLE
regression=# ALTER DEFAULT PRIVILEGES FOR USER joe REVOKE EXECUTE ON FUNCTIONS FROM public;
ALTER DEFAULT PRIVILEGES
regression=# \ddp
           Default access privileges
 Owner | Schema |   Type   | Access privileges 
-------+--------+----------+-------------------
 joe   |        | function | joe=X/joe
(1 row)
 
                                       regards, tom lane

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