Le 13/03/2022 à 15:44, Roger Bos a écrit :
Hello, trying to use CTE to remove duplicates from a table. The DELETE version does not work, but the SELECT version does, so I am not understanding what the problem is. Any suggestions on how to fix it?Here is my query: WITH cte AS( SELECT *, ROW_NUMBER() OVER ( PARTITION BY ticker, date ORDER BY ticker, date) my_row_num FROM price_old)DELETE FROM cte WHERE my_row_num > 1; I get the following error:ERROR: relation "cte" does not exist LINE 3: DELETE FROM cte WHERE my_row_num > 1;But when I run change the query to a select query it runs fine (in that it returns all the duplicate rows). For example:WITH cte AS( SELECT *, ROW_NUMBER() OVER ( PARTITION BY ticker, date ORDER BY ticker, date) my_row_num FROM price_old)SELECT * FROM cte WHERE my_row_num > 1; Sample output:"US000000094541" "AAC" "2022-03-08 00:00:00-05" 9.75 9.76 9.75 9.75 100215 9.75 9.76 9.75 9.75 100215 0 1 2 "US000000094541" "AAC" "2022-03-09 00:00:00-05" 9.75 9.76 9.75 9.76 111334 9.75 9.76 9.75 9.76 111334 0 1 2 "US000000009823" "AAC" "2022-03-10 00:00:00-05" 9.75 9.76 9.74 9.74 170474 9.75 9.76 9.74 9.74 170474 0 1 2 "US000000090393" "ABCL" "2022-03-08 00:00:00-05" 8.19 8.545 7.81 8.22 1984348 8.19 8.545 7.81 8.22 1984348 0 1 2Thanks, Roger
As Michael Lewis says, you can't use delete from cte but you can build your request to do the work with something like (example from you original request) :
WITH cte AS ( SELECT * , ROW_NUMBER() OVER (PARTITION BY a ORDER BY b) my_row_num , ctid -- or pk or other unique identifier if exists FROM price_old ) DELETE FROM tmp24 WHERE ctid IN (SELECT ctid FROM cte WHERE my_row_num = 1); Benj
Attachment:
OpenPGP_signature
Description: OpenPGP digital signature