Re: Counting the number of repeated phrases in a column

[Rob Sargent <robjsargent@xxxxxxxxx>]

On 1/27/22 10:03, Merlin Moncure wrote:

> On Wed, Jan 26, 2022 at 5:23 PM Merlin Moncure <mmoncure@xxxxxxxxx> wrote:
> > with s as (select 'Hello World Hello World' as sentence)
> > select
> >   phrase,
> >   array_upper(string_to_array((select sentence from s), phrase), 1) -
> > 1 as occurrances
> > from
> > (
> >   select array_to_string(x, ' ') as phrase
> >   from
> >   (
> >     select distinct v[a:b]  x
> >     from regexp_split_to_array((select sentence from s), ' ') v
> >     cross join lateral generate_series(1, array_upper(v, 1)) a
> >     cross join lateral generate_series(a + 1, array_upper(v, 1)) b
> >   ) q
> > ) q;
> >       
> Simplified to:
> select distinct array_to_string(v[a:b], ' ') phrase, count(*) as occurrences
> from regexp_split_to_array('Hello World Hello World', ' ') v
> cross join lateral generate_series(1, array_upper(v, 1)) a
> cross join lateral generate_series(a + 1, array_upper(v, 1)) b
> group by 1;
>
>          phrase          │ occurances
> ─────────────────────────┼────────────
>  World Hello             │          1
>  Hello World Hello       │          1
>  Hello World             │          2
>  Hello World Hello World │          1
>  World Hello World       │          1
>
> merlin
>
>
>     
    And since we're looking
      for repeated phrases maybe add
    
> having
>         count(*) > 1
>