Thank you sir and I am sorry for the typo not having "--" on password. I did spelling out with --password=mypassword
>> echo select count(*) from tableA; | "C:\Program Files\PostgreSQL\11\bin\psql" -U PSmasteruser -d PSCIDR -h hostname.amazonaws.com -p 5432 --password=mypassword
even -W for password
>> echo select count(*) from tableA; | "C:\Program Files\PostgreSQL\11\bin\psql" -U PSmasteruser -d PSCIDR -h hostname.amazonaws.com -p 5432 -W=mypassword
none of them work, still prompt me for password to type in. I will look into the pgpassfile which I know it will fail again.
very respectfully,
Bach-Nga
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On Friday, June 19, 2020, 09:19:35 AM EDT, Adrian Klaver <adrian.klaver@xxxxxxxxxxx> wrote:
On 6/19/20 4:12 AM, Pepe TD Vo wrote:
> thank you, I tried that too, remove the quote around the echo and it
> prompt for password, as I mentioned no matter I put -P mypassword no
> matter what I spell out password=mypassword still argument error
Once again -P has nothing to do with password. Also --password does not
take an argument, it is meant to be used as is. The purpose is to force
a password prompt. This is all spelled out here:
https://www.postgresql.org/docs/12/app-psql.html
Also spelled out in above is:
" It is also convenient to have a ~/.pgpass file to avoid regularly
having to type in passwords. See Section 33.15 for more information."
And Section 33.15:
https://www.postgresql.org/docs/12/libpq-pgpass.html
"The file .pgpass in a user's home directory can contain passwords to be
used if the connection requires a password (and no password has been
specified otherwise). ..."
Read more at link for how to do that.
>
> >>echo select count(*) from tableA; | "C:\Program
> Files\PostgreSQL\11\bin\psql" -U PSmasteruser -d PSCIDR -h
> hostname.amazonaws.com -p 5432
>
> >> echo select count(*) from tableA; | "C:\Program
> Files\PostgreSQL\11\bin\psql" -U PSmasteruser -d PSCIDR -h
> hostname.amazonaws.com -p 5432 password=mypassword
>
> all usernames are same password.
>
> thank you so much for all input.
>
> v/r,
>
> **
> *Bach-Nga
--
Adrian Klaver
adrian.klaver@xxxxxxxxxxx
> thank you, I tried that too, remove the quote around the echo and it
> prompt for password, as I mentioned no matter I put -P mypassword no
> matter what I spell out password=mypassword still argument error
Once again -P has nothing to do with password. Also --password does not
take an argument, it is meant to be used as is. The purpose is to force
a password prompt. This is all spelled out here:
https://www.postgresql.org/docs/12/app-psql.html
Also spelled out in above is:
" It is also convenient to have a ~/.pgpass file to avoid regularly
having to type in passwords. See Section 33.15 for more information."
And Section 33.15:
https://www.postgresql.org/docs/12/libpq-pgpass.html
"The file .pgpass in a user's home directory can contain passwords to be
used if the connection requires a password (and no password has been
specified otherwise). ..."
Read more at link for how to do that.
>
> >>echo select count(*) from tableA; | "C:\Program
> Files\PostgreSQL\11\bin\psql" -U PSmasteruser -d PSCIDR -h
> hostname.amazonaws.com -p 5432
>
> >> echo select count(*) from tableA; | "C:\Program
> Files\PostgreSQL\11\bin\psql" -U PSmasteruser -d PSCIDR -h
> hostname.amazonaws.com -p 5432 password=mypassword
>
> all usernames are same password.
>
> thank you so much for all input.
>
> v/r,
>
> **
> *Bach-Nga
--
Adrian Klaver
adrian.klaver@xxxxxxxxxxx
