Regular expressions, in my opinion, can be a very powerful text search and replace engine if you know how to use it.
Feel free to enhance what I provided below; it seems to work for the example you provided.
postgres=# select regexp_replace(substring('Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class X,Class XI,Class IX,Class XII',1,60),'(.*),\w+','\1');
regexp_replace
--------------------------------------------------------
Class V,Class VI,Class VII,Competitive Exam,Class VIII
(1 row)
Regards,
PflugerGeek
PflugerGeek
On Saturday, May 16, 2020, 10:19:28 AM CDT, Alex Magnum <magnum11200@xxxxxxxxx> wrote:
Hi,
Is there a function or easy way to do this?
I have a string that I want to cut to 60 char and then remove the last field and comma.
substring('Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class X,Class XI,Class IX,Class XII',1,60);
substring | Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class
Now I try to remove the last field and comma ",Class"
To get
Class V,Class VI,Class VII,Competitive Exam,Class VIII
Is there a function or easy way to do this?
Any help would be appreciated.
Thank you
Alex