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Re: A question about trigger fucntion syntax

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On Sun, Aug 11, 2019 at 08:56:13AM -0400, stan wrote:
> Good morning (at least is is morning East Coast USA time).
> 
> I am trying to create a function to validate an attempted record 
> insert, and I am having a hard time coming up with syntax that
> is acceptable.
> 
> Here is the scenario I have a table that has (among other items) employee_key
> and work_type_key (both integer FOREIGN KEYS). Then I have another table
> that has the following structure:
> 
> CREATE  TABLE permitted_work (
>     employee_key       integer ,
> 	work_type_key      integer ,
> 	permit             boolean DEFAULT FALSE NOT NULL ,
> 	modtime     timestamptz DEFAULT current_timestamp ,
> 	FOREIGN KEY (employee_key) references
> 	employee(employee_key) ,
> 	FOREIGN KEY (work_type_key) references
> 	work_type(work_type_key) ,
> 	CONSTRAINT permit_constraint UNIQUE
> 			(employee_key , work_type_key)
> 	);
> 
>  What I think I need to do is create a function that is fired on an insert,
>  or update to the 1st table that verifies that there is an existing row in
>  permitted_work that matches the combination of employee_key AND
>  work_type_key AND has the value TRUE in the permit column.
> 
>  First does this seem to be a good way to achieve this constraint? If not,
>  I am open to suggestions as to other ways to address this  requirement. 
> 
>  If it does, could someone give me a little help with th syntax of the
>  needed function ??
> 
>  Thanks for your time helping me with this.

BTW, here is what I Ave tried.

CREATE OR REPLACE FUNCTION check_permission()
  RETURNS trigger AS
$BODY$
BEGIN
	SELECT 
		permit
	FROM
		permitted_work
	WHERE
		NEW.employee_key = OLD.employee_key
	AND
		NEW.work_type_key = OLD.work_type_key
		
   RETURN permit;
END;
$BODY$
LANGUAGE PLPGSQL;

and when I try to insert it I get a syntax error at the RETURN

-- 
"They that would give up essential liberty for temporary safety deserve
neither liberty nor safety."
						-- Benjamin Franklin





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