Hi From: Brahmam Eswar [mailto:brahmam1234@xxxxxxxxx] Hi , I tried to use array_remove to remove elements from an array but it's saying function doesn't exist . I'm able to use other array functions. 1) Capture the results with multiple columns into array . 2) if ay results exist then loop through an array to find out the record with col1='Y' 3) If col1='Y' then get the respective value of Col2 (10) and delete the similar records of col2 if exist. Col1 Col2 Y 10 N 20 N 10 Need to delete record1 and record3.To delete the array records i'm using array_remove but it says doesn't exist. Version pgadmin4 . Snippet :- CREATE or REPLACE FUNCTION FUNC1 ( << List of elements >> ) AS $$ DECLARE TEST_CODES record1 ARRAY; TEMP_REF_VALUE VARCHAR(4000); BEGIN IS_VALID := 'S'; SELECT ARRAY (SELECT ROW(Col1,Col2,COl3,Col4) ::record1 FROM table1 INTO TEST_CODES IF array_length(TEST_CODES, 1) > 0 THEN FOR indx IN array_lower(TEST_CODES, 1)..array_upper(TEST_CODES, 1) LOOP IF TEST_CODES[indx].COL1 = 'Y' THEN TEMP_REF_VALUE:=TEST_CODES[indx].Col2; TEST_CODES := array_remove(TEST_CODES,TEMP_REF_VALUE); END IF; END Loop; END IF; -- Thanks & Regards, I am not so in clear why you are using arrays in a function for that. A solution with SQL would be: CREATE TABLE tst ( col1 text, col2 integer ); INSERT INTO tst VALUES ('Y', 10), ('N', 20), ('N', 10); SELECT * FROM tst; col1 | col2 ------+------ Y | 10 N | 20 N | 10 (3 rows) DELETE FROM tst t USING (SELECT * FROM tst WHERE col1 = 'Y') AS x WHERE t.col2 = x.col2; SELECT * FROM tst; col1 | col2 ------+------ N | 20 (1 row) Regards Charles |
