On 05/16/2018 11:07 AM, Philipp Kraus wrote:
Hello,
I have defined a SQL function
CREATE OR REPLACE FUNCTION substancetrivialname(text)
RETURNS substance
LANGUAGE 'sql'
COST 100
VOLATILE
AS $BODY$
select s.* from substancetrivialname n
join substance s on s.id = n.idsubstance
where lower(btrim(n.name)) = lower(btrim($1));
$BODY$;
substance and substancetrivialname have got a 1-to-N relationship (for each substance can exist multiple trivial names).
If I call the function with a non-existing trivial name it returns a single row with all fields are set to NULL.
Well I was on the right track for the wrong reason. At any rate SETOF works:
select * from cell_per where cell_per = 100;
line_id | category | cell_per | ts_insert | ts_update | user_insert |
user_update | plant_type | season | short_category
---------+----------+----------+-----------+-----------+-------------+-------------+------------+--------+----------------
(0 rows)
CREATE OR REPLACE FUNCTION cp(integer)
RETURNS cell_per
LANGUAGE 'sql'
AS $BODY$
select cell_per.* from cell_per where cell_per = $1;
$BODY$;
select * from cp(100);
line_id | category | cell_per | ts_insert | ts_update | user_insert |
user_update | plant_type | season | short_category
---------+----------+----------+-----------+-----------+-------------+-------------+------------+--------+----------------
NULL | NULL | NULL | NULL | NULL | NULL |
NULL | NULL | NULL | NULL
(1 row)
CREATE OR REPLACE FUNCTION cp(integer)
RETURNS SETOF cell_per
LANGUAGE 'sql'
AS $BODY$
select cell_per.* from cell_per where cell_per = $1;
$BODY$;
select * from cp(100);
line_id | category | cell_per | ts_insert | ts_update | user_insert |
user_update | plant_type | season | short_category
---------+----------+----------+-----------+-----------+-------------+-------------+------------+--------+----------------
(0 rows)
If I run the join query directly it returns an empty record set on a non-existing trivial name.
I expected equal behavior on my function, so my question is, how can I fix this?
Thanks
Phil
--
Adrian Klaver
adrian.klaver@xxxxxxxxxxx
