Alexander Farber wrote: > Here is such a query for the best player > > # SELECT AVG(score) FROM words_moves WHERE uid = 1201; > avg > --------------------- > 18.4803525523319868 > > However I am not sure, how to "marry" the 2 queries? > > I have tried to add words_moves through another JOIN, but that does not > work: You may use a correlated subquery in the SELECT clause, like this: SELECT u.elo, u.uid, (SELECT AVG(score) FROM words_moves WHERE uid=u.uid), s.given, s.photo Best regards, -- Daniel Vérité PostgreSQL-powered mailer: http://www.manitou-mail.org Twitter: @DanielVerite